Linear Algebra Examples

Find the Domain log base 5 of (4x-5)^2=6
log5((4x-5)2)=6
Step 1
Set the argument in log5((4x-5)2) greater than 0 to find where the expression is defined.
(4x-5)2>0
Step 2
Solve for x.
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Step 2.1
Take the specified root of both sides of the inequality to eliminate the exponent on the left side.
(4x-5)2>0
Step 2.2
Simplify the equation.
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Step 2.2.1
Simplify the left side.
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Step 2.2.1.1
Pull terms out from under the radical.
|4x-5|>0
|4x-5|>0
Step 2.2.2
Simplify the right side.
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Step 2.2.2.1
Simplify 0.
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Step 2.2.2.1.1
Rewrite 0 as 02.
|4x-5|>02
Step 2.2.2.1.2
Pull terms out from under the radical.
|4x-5|>|0|
Step 2.2.2.1.3
The absolute value is the distance between a number and zero. The distance between 0 and 0 is 0.
|4x-5|>0
|4x-5|>0
|4x-5|>0
|4x-5|>0
Step 2.3
Write |4x-5|>0 as a piecewise.
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Step 2.3.1
To find the interval for the first piece, find where the inside of the absolute value is non-negative.
4x-50
Step 2.3.2
Solve the inequality.
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Step 2.3.2.1
Add 5 to both sides of the inequality.
4x5
Step 2.3.2.2
Divide each term in 4x5 by 4 and simplify.
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Step 2.3.2.2.1
Divide each term in 4x5 by 4.
4x454
Step 2.3.2.2.2
Simplify the left side.
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Step 2.3.2.2.2.1
Cancel the common factor of 4.
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Step 2.3.2.2.2.1.1
Cancel the common factor.
4x454
Step 2.3.2.2.2.1.2
Divide x by 1.
x54
x54
x54
x54
x54
Step 2.3.3
In the piece where 4x-5 is non-negative, remove the absolute value.
4x-5>0
Step 2.3.4
To find the interval for the second piece, find where the inside of the absolute value is negative.
4x-5<0
Step 2.3.5
Solve the inequality.
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Step 2.3.5.1
Add 5 to both sides of the inequality.
4x<5
Step 2.3.5.2
Divide each term in 4x<5 by 4 and simplify.
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Step 2.3.5.2.1
Divide each term in 4x<5 by 4.
4x4<54
Step 2.3.5.2.2
Simplify the left side.
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Step 2.3.5.2.2.1
Cancel the common factor of 4.
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Step 2.3.5.2.2.1.1
Cancel the common factor.
4x4<54
Step 2.3.5.2.2.1.2
Divide x by 1.
x<54
x<54
x<54
x<54
x<54
Step 2.3.6
In the piece where 4x-5 is negative, remove the absolute value and multiply by -1.
-(4x-5)>0
Step 2.3.7
Write as a piecewise.
{4x-5>0x54-(4x-5)>0x<54
Step 2.3.8
Simplify -(4x-5)>0.
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Step 2.3.8.1
Apply the distributive property.
{4x-5>0x54-(4x)--5>0x<54
Step 2.3.8.2
Multiply 4 by -1.
{4x-5>0x54-4x--5>0x<54
Step 2.3.8.3
Multiply -1 by -5.
{4x-5>0x54-4x+5>0x<54
{4x-5>0x54-4x+5>0x<54
{4x-5>0x54-4x+5>0x<54
Step 2.4
Solve 4x-5>0 for x.
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Step 2.4.1
Add 5 to both sides of the inequality.
4x>5
Step 2.4.2
Divide each term in 4x>5 by 4 and simplify.
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Step 2.4.2.1
Divide each term in 4x>5 by 4.
4x4>54
Step 2.4.2.2
Simplify the left side.
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Step 2.4.2.2.1
Cancel the common factor of 4.
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Step 2.4.2.2.1.1
Cancel the common factor.
4x4>54
Step 2.4.2.2.1.2
Divide x by 1.
x>54
x>54
x>54
x>54
x>54
Step 2.5
Solve -4x+5>0 for x.
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Step 2.5.1
Subtract 5 from both sides of the inequality.
-4x>-5
Step 2.5.2
Divide each term in -4x>-5 by -4 and simplify.
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Step 2.5.2.1
Divide each term in -4x>-5 by -4. When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.
-4x-4<-5-4
Step 2.5.2.2
Simplify the left side.
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Step 2.5.2.2.1
Cancel the common factor of -4.
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Step 2.5.2.2.1.1
Cancel the common factor.
-4x-4<-5-4
Step 2.5.2.2.1.2
Divide x by 1.
x<-5-4
x<-5-4
x<-5-4
Step 2.5.2.3
Simplify the right side.
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Step 2.5.2.3.1
Dividing two negative values results in a positive value.
x<54
x<54
x<54
x<54
Step 2.6
Find the union of the solutions.
x<54 or x>54
x<54 or x>54
Step 3
The domain is all values of x that make the expression defined.
Interval Notation:
(-,54)(54,)
Set-Builder Notation:
{x|x54}
Step 4
 [x2  12  π  xdx ]